A diver runs horizontally off the end of a diving board with an initial speed of 1.95 m/s. If the diving board is 2.00 m above the water, what is the diver's speed just before she enters the water

V = 6.56 m/s

Explanation:

in order to find the speed of the diver before she enters we need to find the vertical component of its final velocity by using 3rd equation of motion:

2gh = Vy² - V₀y²

where,

g = 9.8 m/s²

h = height = 2 m

Vy = Vertical Component of Final Velocity = ?

V₀y = Vertical Component of Initial Velocity = 0 m/s

Therefore,

2(9.8 m/s²)(2 m) = Vy² - (0 m/s)²

Vy = √39.2 m²/s²

Vy = 6.26 m/s

Assuming negligible air friction, the x-component of the final velocity will be the same as the initial velocity:

Vₓ = V₀ₓ = 1.95 m/s

Hence, the final velocity will be:

V = √(Vₓ² + Vy²)

V = √[(1.95 m/s)² + (6.26 m/s)²]

V = 6.56 m/s

hypothesising or postulating

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles