A mass of 0.250 kg is attached to a spring and undergoes simple harmonic oscillations with a period of 0.640 s. What is the force constant of the spring?

The force constant of the spring is approximately 24.038 newtons per meter.

As we are talking about Simple Harmonic Motion. In this exercise we need to determine the Spring Constant (), in newtons per meter, from the equation of the Period (), in seconds, which is described below:

(1)

Where is the mass of the moving element, in kilograms.

If we know that and , then the spring constant of the spring is:

The force constant of the spring is approximately 24.038 newtons per meter.

Please see this question related to Simple Harmonic Motion for further details: link

Force constant of the spring (k) = 24.07 N/m

Concept/Theory:

The period of a spring-mass system is proportional to the square root of the mass (m) and inversely proportional to the square root of the force constant of the spring (k).

Equation of period:

Explanation:

Mass = 0.250 kg

Period = 0.640 s

By substituting values in the equation, we get:

iron would move it is magnetic there is a mag field around the current in the wire

v=ir = 3x15 =45 v