A car is traveling 60 km/h and accelerates at a rate of 4 m/s^2 how long does it take the car to get to 90 km/h? ( please show work)

Vf = 90km/h

      (90*1000)/3600 ==>

      (90*10)36

Vf = 25m/s

, Vi = 60km/h

         (60*1000)/3600

          16.666m/s =>16.7m/s

          , a = 4m/s^2

t = ?

Explanation:

Vf = Vi + at

25m/s = 16.7m/s +4m/s^2(t)

25m/s - 16.7m/s = 4m/s^2(t)

8.3m/s = 4m/s^2(t)

8.3m/s/4m/s^2 = t

2.075s = t => 2.1s

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

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