A block slides down a 30.0 degree inclined plane at an acceleration of 2.0 m/s^2. What is the coefficient of friction between the block and the inclined plane? Use g=10.0 m/s^2 A) .20
B) .25
C) .30
D) .35

D) .35

Explanation:

m = Mass of block

g = Acceleration due to gravity =

= Angle of inclination =

a = Acceleration of block =

= Coefficient of friction between the block and the inclined plane

f = Frictional force =

As the forces are conserved in the system we have

The coefficient of friction between the block and the inclined plane is 0.35

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s