This is a graph of a car speeding up and then reaching a constant speed of 105 m/s . After it finishes speeding up, how far does the car travel during the last 6 seconds of the graph, from 4 to 10 s?

60 m

Concept Used:

We know that the area under a velocity-time graph represents the Displacement of the body

Displacement in the Last 6 seconds:

To find the Displacement in the last 6 seconds, we will find the area under the graph between x = 4 and x = 10

We can see that the shape formed is a rectangle also shown in the given graph. So, the area of the rectangle is the Displacement of the car in the last 6 seconds

Area of the Rectangle:

From the graph, we know that the rectangle is 10 (m/s) tall and 6 (s) wide

Area of Rectangle=  length*Breadth        

replacing the values

Area = 10 (m/s) * 6 (s)

Area = 60 m

Hence, the car travelled 60 m in the last 6 seconds of the graph

probably not if net force is zero

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.