PLEASE HELP ME ANSWER THESE TWO QUESTIONS. 1) If the coefficient of kinetic friction between the box and the ramp is 0.298, what is the force of friction that opposes Cory and Kathy’s pushing forces?

2) Cory is pushing to the right (up the ramp) with a force of 379 N, and Kathy is pushing to the right with a force of 357 N. What is the magnitude of the acceleration of the box?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Ifound this answer online hope it

Iwas thinking the wavelength is one half its original value