There is a species of Darwin’s finch on the Galapagos Islands that can exert a force of 205N with its beak as it cracks open a seed case. If its beak moves through a distance of 0.40 cm during this operation, how much work does the finch do to get at the seed inside the case?

0.82 J

Explanation:

We know that work done W = Fd where F = force and d = distance moved in the direction of the force.

Now, the finch on Galapagos Islands exerts a force of 205 N with its beak as it cracks open a seed case. So, F = 205 N. If the beak moves a distance of 0.40 cm during this operation, then d = 0.40 cm = 0.004 m.

We now compute W.

So, W = Fd

= 205 N × 0.004 m

= 0.82 J

So the finch does work of 0.82 J to get at the seed inside the case.

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)