Under what conditions the reaction rate of an enzymolysis that follows Michaelis-Menten kinetics is a quarter of its maximum value? a. [S]=KM
b. [S]=KM/3
c. [S]=2KM
d. [S]=KM+3
e. [S]= (KM)^1/3

Solution :

Michaelis-Menten kinetics in the field of biochemistry is considered as one of the well known models for enzyme kinetics. The model represents an equation that describes the enzymatic reactions's rate by relating the reaction rate to the substrate's concentration. The equation is named after the two famous scientists,  Leonor Michaelis and Maud Menten.

The formula is :

where v = velocity of reaction

            = maximum rate achieved

            = Michaelis constant

           [S] = concentration of the substrate, S

According to the question, by putting the velocity of reaction, v as , we get the above equation as

Therefore the answer is

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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