Suppose three forces are acting on a model rocket launching into the air. The force of gravity is 1.2 N acting downward. The rocket engine has a force of 12.3 N acting at an angle of 65⁰ above the horizontal to the right. The wind pushes the rocket with a force of 2.5 N to the left. Find the magnitude and direction of the resultant force on the rocket. Please answer!!! Offering 50 points for answer and explanation

Decompose the forces acting on the rocket in horizontal and vertical components.

• net horizontal force:

∑ F = (12.3 N) cos(65°) - 2.5 N ≈ 2.7 N

(notice we're taking "to the right" to be the positive direction)

• net vertical force:

∑ F = (12.3 N) sin(65°) - 1.2 N ≈ 9.9 N

The resultant force then has magnitude

√((2.7 N)² + (9.9 N)²) ≈ 10.3 N

Since the horizontal and vertical components of the resultant are both positive, it points at an angle between 0° and 90° from the positive horizontal, so that

tan(θ) ≈ (9.9 N) / (2.7 N) ≈ 3.69

===>   θ ≈ arctan(3.69) ≈ 75°

an ion is a charged atom or molecule. it is charged because the number of electrons do not equal the number of protons in the atom or molecule. an atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom.

hi i’m sorry to call us today so we will get back with y’all and we will have to do it haha omg was the day