Physics, 02.12.2020 01:30 darianhaynes

1. *A car is going over the top of a hill whose curvature approximates a circle of radius 200 m. At what velocity will the occupants of the car appear to weigh 20% less than their normal weight (or
their normal weight times 0.8)?

Answers: 3

Show answers

Answers

The velocity is 19.81 m/sec at which the occupants of the car appear to weigh 20% less than their normal weight and this can be determined by using the formula of centripetal force.

Given :

A car is going over the top of a hill whose curvature approximates a circle of radius 200 m.

The centripetal force acting on the car is given by the formula:

$\rm F_c = \dfrac{mv^2}{r}$ ---- (1)

where m is the mass of a car, v is the velocity of the car and r is the radius of curvature.

Now, it is given that the occupants of the car appear to weigh 20% less than their normal weight that means:

$\rm F_c = 0.2\times W$

$\rm F_c = 0.2 \times m \times g$ --- (2)

Now, equate equation (1) with equation (2).

$\rm \dfrac{mv^2}{r}=0.2\times m \times g}{}$

$\rm v = \sqrt{0.2\times g \times r }$

$\rm v = \sqrt{0.2\times 9.81 \times 200 }$

v = 19.81 m/sec

The velocity is 19.81 m/sec at which the occupants of the car appear to weigh 20% less than their normal weight.

For more information, refer to the link given below:

link

Answer from: aide1234564

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s

Explanation:

The given parameters are;

The curvature of the hill, r = 200 m

Due to the velocity, v, the occupants weight = 20% less than the normal weight

The outward force of an object due to centripetal (motion) force is given by the following equation;

$F_c = \dfrac{m \times v^2}{r}$

Where;

r = The radius of curvature of the hill = 200 m

Given that the weight of the occupants, W = m × g, we have;

$F_c = 0.2 \times W = 0.2 \times m \times g$

$\therefore 0.2 \times m \times g = \dfrac{m \times v^2}{r}$

v = √(0.2 × g × r)

By substitution, we have;

v = √(0.2 × 9.81 × 200) ≈ 19.81

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.

Answer from: Quest

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.

Answer from: Quest

v=ir = 3x15 =45 v

Another question on Physics

Physics, 23.06.2019 00:20

When can a theory be modified if a new type of technology allows for new observations that raise new questions? a-immediately, while the questions about the theory are being asked b-after new hypotheses related to the theory are tested in experiments c-only after the new observations disprove all parts of the theory d-while scientists begin to think about how the theory could improve

Answers: 1

Answer

Physics, 23.06.2019 00:30

Which of the following statements accurately describes the sign of the work done on the box by the force of the push? a. positive b. negative c. zero

Answers: 3

Answer

Physics, 23.06.2019 07:00

Calculate the linear momentum of a pickup truck that has a mass of 1000kg, and is traveling eastward at 20 m/s

Answers: 1

Answer

Physics, 23.06.2019 15:30

An airplane travels from st. louis to portland, oregon in 4.33 hours. if the distance traveled is 2,742 kilometers. what is the airplane's average speed? - the airplane returns to st. louis by the same route. because the prevailing winds push the airplane along, the return trip takes only 3.75 hours. what is the average speed for this trip? - the airplane refuels in st. louis and continues on to boston. it travels at an average speed of 610 km/h. if the trip takes 3.75 hours. what is the flight distance between st. louis and boston?

Answers: 3

Answer

You know the right answer?

1. *A car is going over the top of a hill whose curvature approximates a circle of radius 200 m. At...

Questions