A spy satellite of mass of 1000 kg is orbiting the earth at an altitude of 300 km/s a) what is its period
b) what is its orbital speed

a) The period of the satellite is approximately 5,425.305 seconds (1.507 hours)

b) The orbital velocity of the satellite is approximately 7,725.8565 m/s

Explanation:

The given parameters are;

The mass of the satellite, m = 1,000 kg

The altitude at which the satellite is orbiting, h = 300 km

a) The period of the satellite is given as follows;

Where;

R = The radius of the Earth = 6.371 × 10⁶ m

g = The acceleration due to gravity = 9.81 m/s²

h = The altitude of the orbit of the satellite = 300 km = 300,000 m

By substitution, we have;

T ≈ 5,425.305 seconds ≈ 1.507 hours

b) The orbital velocity of the satellite is given as follows;

Where;

v₀ = The orbital velocity of the satellite

Which by substitution gives;

The orbital velocity, v₀ = 7,725.8565 m/s.