Two friends are competing in an odd game of bowling in which the object of the game is to roll the bowling ball towards the pins and get the ball to stop as close to the pins as possible without hitting them. Shawn began with a 7 pound bowling ball and was able to come within an inch of the pins. If he is given a 14 pound bowling ball on his next turn, how should he go about modifying his method in order to come just as close? A. He should apply half of the force as he did with the lighter ball, since the heavier ball has less inertia because it has double the mass.

B. He should apply twice the force as he did with the lighter ball, since the heavier ball has more inertia because it has double the mass.

C. He should apply the same force as he did with the lighter ball, since the bowling alley will still apply the same force of friction against any ball regardless of weight.

D. He should apply the same force as he did with the lighter ball, since all objects will travel at the same rate of acceleration due to gravity regardless of weight.

B.He should apply twice the force as he did with the lighter ball, since the heavier ball has more inertia because it has double the mass.

Explanation:

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation:

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.