Question 5 (1 point) A child kicks a ball horizontally with a speed of 4.8 m/s off a deck 3.5 m off the
ground. How far, in meters, from the deck does the ball land on the ground?

The horizontal distance the ball travels is approximately 4.055 meters

Explanation:

The given parameters are;

The height from which the child kicks the ball = 3.5 m

The horizontal speed of the ball = 4.8 m/s

Therefore, we have;

The time it takes the ball to hit the ground is given by the relation;

h = u·t + 1/2·g·t²

Where;

u = The initial vertical velocity of the ball = 0 m/s

t = The time it takes the ball to hit the ground

g = The acceleration due to gravity = 9.81 m/s²

h = The height of the ball = 3.5 m

3.5 = 0 × t + 1/2 × 9.81 × t²

3.5 = 1/2 × 9.81 × t²

∴ t² = 3.5/(1/2 × 9.81)

∴ t = √(3.5/(1/2 × 9.81) = 0.8447 s

t ≈ 0.8447 s

The time the ball takes in flight = t ≈ 0.8447 s

Therefore;

The horizontal distance the ball travels = The horizontal velocity × The time of flight

∴ The horizontal distance the ball travels = 4.8 × 0.8447 ≈ 4.055

The horizontal distance the ball travels ≈ 4.055 meters.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.