1 a ) A 1500 kg car is driving 30 m/s on the highway. The car reaches an off-ramp and slows to 15 m/s. How much impulse is applied to the car? 1 b ) How much force is required for the car in the previous question to complete its deceleration a) in 10 seconds, and b) in 5 seconds?

I'll do it rn and then answer

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j