The circuit diagram shows three resistors connected in series across a 6.0V supply. 6.0V
+
3.092
4.092
5.012
What is the potential difference (p. d.) across the 4.0 12 resistor?
A) 0.67 V
B) 1.5 V
C) 2.0 V
D) 6.0V

the correct answer is option C , 2.0 V( volts ) !!

explanation : Total potential difference = 6 V

Total resistance = ( 3 + 4 + 5 ) ohms = 12 ohms

so , applying ohm's law to the whole circuit , we get :

V/ I = R

6/ I = 12

I = 6/ 12 = 1/2 = 0.5 ( total current ) ampere or A

now Current through 4 Ohms Resistance = 0.5 A

Resistance we know= 4 Ohms

Applying ohm's law :

V/I = R

V/0.5 = 4

V = 0.5 × 4 = 2 V

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

are their multiple choices ?

explanation: