7.A ball falls from rest for 0.67 seconds, what is its final speed just prior to hitting the ground?

v = 6.57 m/s

Explanation:

if we use SUVAT equation , v = u + at

a = acceleration = 9.81 (if air resistance is negligible)

t = 0.67

u = 0 (as initial speed was 0, the ball increases the speed after)

v = 0 + (9.81)(0.67)

v = 6.57 m/s

good looking response

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.