A clock which has brass pendulum beats seconds correctly when the temperature of the room is 30° C. how many seconds will it gain or lose per day when the temperature of the room falls to 10° C?

A::C

Solution :

ΔT=

1

2

TαΔθ

rArr Δt=

ΔT

T1t

But T′≈T

∴Δt=

1

2

αΔθ(t)

=

1

2

×0.000012×20×24×3600

=10.37s

At higher temperture, length of pendulum clock will be more. So, time period will be more and it will lose the time.

Explanation:

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)

c. magnitude and direction