A shear force of 400 N is applied to one face of an aluminum cube with sides of 30 cm. What is the resulting relative displacement? (the shear modulus for aluminum is 2.5x1010N/m2)

5.3 × 10^(-8) m

Explanation:

We are given;

Shear force; F = 400 N

Length of cube; L_o = 30 cm = 0.3 m

Shear modulus; S = 2.5 × 10^(10) N/m²

Now,the resulting relative displacement can be gotten from the formula;

F = A × S × Δx/L_o

Where Δx is resulting relative displacement

A is area.

Area of cube = (L_o)² = 0.3² = 0.09

Thus, making Δx the subject, we have;

Δx = (F × L_o)/(A × S)

Plugging in the relevant values;

Δx = (400 × 0.3)/(0.09 × 2.5 × 10^(10))

Δx = 5.3 × 10^(-8) m

absorption lines are where light has been absorbed by the atom thus you see a dip in the spectrum whereas.

emission spectra have spikes in the spectra due to atoms releasing photons at those wavelengths.

explanation:

the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

the dependent variable, the one that you measure the response in, is the distance that the washers travel.