A 65-kg swimmer pushes on the pool wall and accelerates at 6 m/s^2. The friction experienced by the swimmer is 100 N. How many N of force does the swimmer applies a force of

The force the swimmer applied when he pushes on the pool wall is 490 N.

The given parameters;

The force applied by the swimmer is calculated by applying Newton's second law of motion as shown below;

F = ma

∑F = 0

F - Fk = ma

F = Fk + ma

F = 100 + (65 x 6)

F = 490 N

Thus, the force the swimmer applied when he pushes on the pool wall is 490 N.

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490N

Explanation:

According Newton's second law!

\sum Force = mass × acceleration

Fm - Ff = ma

Fm is the moving force

Ff s the frictional force = 100N

mass = 65kg

acceleration = 6m/s²

Required

Moving force Fm

Substitute the given force into thr expression and get Fm

Fm -100 = 65(6)

Fm -100 = 390

Fm = 390+100

Fm = 490N

Hence the force that will cause two cart to move is 490N

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)