Three resistors of resistances 2 Ω, 3 Ω and 4 Ω are connected in series with a 15 V supply. Calculate the i) total resistance of the circuit i) total current iii) voltage drop across each resistance.

Given that,

Three resistors of resistances 2 Ω, 3 Ω and 4 Ω are connected in series with a 15 V supply.

Solution,

The equivalent resistance in series combination is given by :

(i) Total resistance of the circuit is equal to 9 ohms.

(ii) Let I be the total current. Using Ohm's law as follows :

(iii) Voltage drop across 2 ohm resistor is :

Voltage drop across 3 ohm resistor is :

Voltage drop across 4 ohm resistor is :

Hence, this is the required solution.

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

do you have a formula possibly