An unknown material, m1 = 0.41 kg, at a temperature of T1 = 86 degrees C is added to a Dewer (an insulated container) which contains m2 = 1.7 kg of water at T2 = 22 degrees C. Water has a specific heat of cw = 4186 J/(kg⋅K). After the system comes to equilibrium the final temperature is T = 30.3 degrees C.

Complete Question

An unknown material, m1 = 0.41 kg, at a temperature of T1 = 86 degrees C is added to a Dewer (an insulated container) which contains m2 = 1.7 kg of water at T2 = 22 degrees C. Water has a specific heat of cw = 4186 J/(kg⋅K). After the system comes to equilibrium the final temperature is T = 30.3 degrees C.

Part (a) Input an expression for the specific heat of the unknown material.

Part (b) What is the specific heat in J/(kg⋅K)?

a

b

Explanation:

From the question we are told that

    The mass of the material is  

     The temperature is  

      The mass of water is  

      The temperature of water is  

      The specific heat of water is  

       The temperature of the system is  

Generally heat lost by the unknown material =  heat gained by water

Generally the heat gained by water is mathematically represented as  

=>      

=>      

Generally the heat lost by the unknown material  is mathematically represented as        

=>      

Here  c is the specific heat capacity of the unknown material

=>      

=>              

So

=>        

=>        

prolly a beacuse the momentuem the car has increases while going down hill

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.