John is pushing (horizontally) on a 100 kg (Fw = 980N) bench with an unknown force. If the coefficient of static friction is 0.20 and the acceleration is 1.84m/s/s, what is the applied force?

1176N

Explanation:

Given parameters:

Mass of bench  = 100kg

Forward force  = 980N

Coefficient of static friction = 0.2

Acceleration  = 1.84m/s²

Unknown:

Magnitude of the applied force  =?

Solution:

Frictional force is a force that opposes motion, for a body to move, the applied force must be greater than the frictional force;

The Force applied;

  Force applied  = Frictional force + Weight of the body

   Frictional force  = umg

     u is the coefficient of static friction

      m is the mass

        g is the acceleration due to gravity

    Force applied  = 0.2 x 100 x 9.8 + 980 = 1176N

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation