A grindstone increases in angular speed from 4.00 rad/s to 12.00 rad/s in 4.00 s. Through what angle does it turn during that time if the angular acceleration is constant? a. 8.00 rad
b. 12.00 rad
c. 16.0 rad
d. 32.0 rad

d. 32.0 rad

Explanation:

The angular speed, denoted by ω can be calculated thus;

ω = θ /t

Where;

ω = angular speed in radians/sec

θ = angle in radians

t = time in seconds

∆ω = final ω - initial ω

ω = 12.00 rad/s - 4.00 rad/s

ω = 8.00 rad/s

Hence, using ω = θ/t

8.00 = θ/4

θ = 32.00rad

that would be because of both gravity and friction. so     c