How do I find net force when something has arrows all four directions with different N values for each? In the free-body diagram shown above, which of the following is the net force on the balloon?
1570 N
-570 N
1212 N
1070 N
Image shows arrows:
Pointing to right=950N
To left=1520N
up=5120N
down=4050N

In the vertical direction, take up to be positive and down to be negative. Then the net vertical force would be

5120 N - 4050 N = 1070 N

(it's positive, so the net vertical force is pointing upward)

In the horizontal direction, take right to be positive and left to be negative. Then the net horizontal force would be

950 N - 1520 N = -570 N

(negative means the net horizontal force points to the left)

So the net force on the balloon is the vector

F = (1070 N) i + (-570 N) j

(where i and j are the unit vectors in the horizontal and vertical directions, respectively)

The magnitude of the net force on the balloon is the magnitude of this vector:

F = √((1070 N)² + (-570 N)²)

F ≈ 1212 N

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!