What is the acceleration of a softball with a mass 0.5kg that is thrown with a force of 25 N?

50 m/s^2

Explanation:

F=ma

25 N= 0.5 kg • a

divide both sides by 0.5 kg

a=50 m/s^2

50 inches should be the resultant vector

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.