A boat uses its motor to increase its speed from 5 m/s to 7 m/s. If the boat has a mass of 250 kg, what was the impulse applied by the motor?

J = 500 kg-m/s

Explanation:

Given that,

Initial speed of the motor, u = 5 m/s

Final speed of the motor, v = 7 m/s

Mass of the boat, m = 250 kg

We need to find the impulse applied by the motor. We know that impulse is equal to the change in momentum. It is represented by letter J.

J = m(v-u)

J = 250 (7-5)

J = 500 kg-m/s

Hence, the impulse applied by the motor is 500 kg-m/s.

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.

i think the answer is tomato juice? not entirely sure though