Height of cannon 5 m, initial speed of projectile 15m/s, angle of launch 0 degrees. What is the range and time in the air? Please show work!

The range is 15.15 m and the time in the air is 1.01 s

Explanation:

Horizontal Motion

When an object is thrown horizontally (with angle 0°) with a speed v from a height h, it follows a curved path ruled exclusively by gravity until it eventually hits the ground.

The range or maximum horizontal distance traveled by the object can be calculated as follows:

To calculate the time the object takes to hit the ground, we use the equation below:

The cannon is shot from a height of h=5 m with an initial speed of v=15 m/s. The range is calculated below:

d = 15.15 m

The time in the air is:

t = 1.01 s

The range is 15.15 m and the time in the air is 1.01 s

33: i think it’s b

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2