A 1.3 kg mass starts from rest and slides down an inclined plane 8.7 ✕ 10-1 m long in 0.37 s. What net force is acting on the mass along the incline?

The net force acting on the mass along the incline is 16.523 N

From the information given:

According to the second equation of motion;

the initial velocity u = 0 m/s since the mass starts from the rest

∴

2S = at²

acceleration (a) = 12.71 m/s²

The net force now acting on the mass along the incline can now be estimated as:

Therefore, we can conclude that the net force acting on the mass along the incline is 16.523 N

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The net force acting on the mass is 16.523 N

Explanation:

The given mass of the object, m = 1.3 kg

The length of the inclined plane over which the mass slides = 8.7 × 10⁻¹ m

The time it takes the mass to slide = 0.37 s

Therefore, we apply the following kinematic equation of motion;

s = u·t + 1/2·a·t²

Where;

u = The initial velocity of the mass = 0 m/s

t = The time taken for the motion = 0.37 s

a = The acceleration

s = The distance moved in the motion = 8.7 × 10⁻¹ m = 0.87 m

Plugging in the values gives;

0.87 = 0 × t + 1/2 × a × 0.37²

∴ 0.87 = 1/2 × a × 0.37²

a = 0.87/(1/2 × 0.37²) ≈ 12.71 m/s²

The net force acting on the mass is F = Mass, m × Acceleration, a force = m × a

Therefore, the net force acting on the mass is F = 1.3 × 12.71 = 16.523

The net force acting on the mass, F = 16.523 N.

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