Physics, 12.12.2020 17:00 anaroles04

The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at the instant the first touches the ground. How far above the ground is the second drop at that instant? I will mark brainliest

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Answer from: Christyy1837

The second drop is 3.75 m above the ground

Explanation:

Free Fall Motion

A free-falling object falls under the sole influence of gravity without air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is g = 9.8 m/s^2 .

The distance traveled by a dropped object is:

$\displaystyle y=\frac{gt^2}{2}$

If we know the height h from which the object was dropped, we can find the time it takes fo hit the ground:

$\displaystyle t=\sqrt{\frac{2y}{g}}$

When the first drop touches the ground there are two more drops in the air: the second drop still traveling, and the third drop just released from the tap.

The total time taken for the first drop to reach the ground is:

$\displaystyle t_1=\sqrt{\frac{2*5}{g}}$

$t_1 = 1.01\ s$

Half of this time has taken the second drop to fall:

$t_2 = 1.01\ s/2=0.505\ s$

It has fallen a distance of:

$\displaystyle y_2=\frac{9.8(0.505)^2}{2}$

$y_2 = 1.25\ m$

Thus its height is:

h = 5 - 1.25 = 3.75

The second drop is 3.75 m above the ground

Answer from: Quest

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2 y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x | y

-2 | 2

0 | 8

2 | 14

Create a table of x and y values for the expression y/4=3/4x+2. use the x values of -2,0, and 2. i n

Answer from: Quest

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