A horizontal wire PQ is perpendicular to a uniform horizontal magnetic field. A length of 0.25 m of the wire is subject to a magnetic field strength of 40 mT. A downward magnetic force of 60 mN acts on the wire. What is the magnitude and direction of the current in the wire

Complete question:

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The magnitude of the current is 6 A, in the direction of Q to P.

Explanation:

Given;

length of the wire, l = 0.25 m

magnetic field strength, B = 40 mT = 0.04 T

Magnitude of the magnetic force, F = 60 mN = 0.06 N

The magnitude of the current in the conductor is given as;

F = BIL

Where;

I is the current induced in the conductor

I = F / BL

I = (0.06) / (0.04 x 0.25)

I = 6 A

Th current will move in direction of Q to P

Neptune is the eighth planet from the sun. it was the first planet to get its existence predicted by  mathematical calculations  before it was actually seen through a telescope on sept. 23, 1846. irregularities in the orbit of  uranus  led french astronomer alexis bouvard to suggest that the gravitational pull from another celestial body might be responsible. german astronomer johann galle then relied on subsequent calculations to   spot neptune via telescope. previously, astronomer galileo galilei sketched the planet, but he mistook it for a star due to its slow motion. in accordance with all the other planets seen in the sky, this new world was given a name from greek and roman mythology — neptune, the roman god of the sea.