A golfer hits a ball and gives it an initial velocity of 40 m/s, at an angle of 30 degrees above the horizontal. A) how long does the ball stay in the air? (Answer is 4.08 sec)

B) how far horizontally (the range) does the ball travel before hitting the ground? (Answer 141 m)

I need help with getting the work. If y’all could explain, that would be so helpful and thank you.

(a) The ball will stay in the air for 4.08 s.

(b) The ball travels 141 m horizontally before hitting the ground.

This is a projectile motion problem, to solve the problems above, we need to use the formula of (a) Time of flight and (b) Range.

(a)

⇒ Formula

⇒Where:

From the question,

⇒Given:

⇒Assuming:

⇒Substitute these values into equation 1

Also,

(b) For Range

⇒ Formula

⇒Substitute these values above into equation 2

Hence, (a) The ball will stay in the air for 4.08 s (b) The ball travels 141 m horizontally before hitting the ground

Learn more about projectile motion here: link

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.