A ball is thrown upward at 25 m/s from the ground. What is the maximum height of the ball?

31.25 meters in a time of 2.5 seconds.

Explanation:

Because your question gives a number that is a multiple of 5, that is just begging for us to set a = -g = -10 m/s^2. This is acceleration due to gravity. Then, we have an equation vf = v0 + at where v0 = 25 m/s. Plugging in the earlier known values and letting vf = 0 (when final velocity is zero there is maximum height), we get t = 2.5 s. Then, Delta y = vot - 1/2 gt^2. This gives 62.5 - 31.25 = 31.25 m.

Thus, our answer is 31.25 meters in a time of 2.5 seconds.

*Note: g is more precisely 9.806 m/s^2, but that would lead to more annoying sig figs in our answer so I chose to round to 10 m/s^2 which is common.

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2