What is the force of gravity acting on a 2000 kg spacecraft when it is about the Earth at a in orbit distance of 8.375 x 106 m?

W = 13.44 KN

Explanation:

First, we need to find the value of acceleration due to gravity at the specified height:

where,

g' = value of acceleration due to gravity at given height = ?

g = value of acceleration due to gravity at surface of earth = 9.81 m/s²

h = height of space craft = 8.375 x 10⁶ m - 6.37 x 10⁶ m = 2.005 x 10⁶ m

R = Radius of Earth = 6.37 x 10⁶ m

Therefore,

Now, we can find the weight or force of gravity on space craft:

where,

W = Force of gravity on space craft = ?

m = mass of space craft = 2000 kg

Therefore,

W = 13.44 KN

bacteria that live on the ocean floor are sustained by phytoplankton. phytoplankton, microscopic marine photosynthetic organisms, have a vastly significant role to play not only in the marine food web of which they’re part of, but also on a more global scale. despite their infinitely small size in comparison to other marine organisms, these tiny creatures occupy an immensely important ecological niche: they are the foundation of the marine food web, and as primary producers, play key roles in supporting all other organisms in the marine environment, as well as in the regulation of the earth’s climate through the sequestration of carbon, oxygen production, and other related processes. phytoplankton account for roughly half of all global primary productivity; therefore, their significance extends far beyond the marine environment alone. there is an intriguing sense of irony in the realization that these tiny living beings that often live out their existence unnoticed and undetected by the rest of the world, have such a far-reaching impact on the lives of virtually all other living organisms on the planet, particularly on those in the marine environment. the world that we have become accustomed to has been and is continuously shaped by the workings of these miniscule yet vital “plants of the sea”.

hope this !