A particle is moving with simple harmonic motion of period 8•0 s and amplitude 5•0 m Fine (A). The speed of the particle when it's 3•0 m from the centre of it's motion (B). The maximum speed (C). The maximum acceleration

a. v(1.8) = -3.14 m/s

b.

c.

Explanation:

a.

The speed of a particle executing simple harmonic motion is given by the following equation:

where,

v = velocity = ?

A = Amplitude = 5 m

ω = angular frequency = = 0.785 s

t = time

First we find time at 3 m by using equation for displacement:

Therefore,

v(1.8) = -3.14 m/s

c.

The maximum speed is given as:

The maximum acceleration is given as: