Calculate the magnetic field strength needed on a 200-turn square loop 20.0 cm on a side to create a maximum torque of 300 N-m if the loop is carrying current of 25.0 A.

The magnetic field strength needed is 1.5 T.

Explanation:

Given;

number of turns, N = 200 turn

length of the each side of the square loop, L = 20 cm = 0.2 m

maximum torque created, τ = 300 N-m

current through the loop, I = 25 A

The maximum torque created in the is the loop is given by;

τ = NIBA

Where;

B is the magnetic field strength, which is calculated as;

Therefore, the magnetic field strength needed is 1.5 T.

like poles repel so keep pushing north to north and repels funny to see this

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer