How many turns should a solenoid of cross-sectional area 3.0×10−2 m2 and length 0.24 m have if its inductance is to be 36 mH ?

The number of turns of the solenoid is 478.7 turns.

Explanation:

Given;

area of the solenoid, A = 3.0 x 10⁻² m²

length of the solenoid, l = 0.24 m

inductance of the solenoid, L = 36 mH = 0.036 H

The number of turns of the solenoid is calculated as follows;

Therefore, the number of turns of the solenoid is 478.7 turns.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y