A cylindrical pulley is driven by a belt. The pulley is a cylinder with radius 0.0160 m and mass 2.75 kg. The tension in the belt is 30.0 N. a. Calculate the torque on the pulley.
b. Calculate the moment of inertia of the pulley.
c. Calculate the angular acceleration of the pulley.
d. If the pulley begins at rest, how long will it take to reach 285 rpm

0.48Nm ; 0.000352kgm^-2 ; 1363.6363 rad/sec ;

Explanation:

A cylindrical pulley is driven by a belt. The pulley is a cylinder with radius 0.0160 m and mass 2.75 kg. The tension in the belt is 30.0 N.

a. Calculate the torque on the pulley.

b. Calculate the moment of inertia of the pulley.

c. Calculate the angular acceleration of the pulley.

d. If the pulley begins at rest, how long will it take to reach 285 rpm

Given that :

Radius (r) = 0.0160 m

Mass (m) = 2.75 kg

Tension in belt (F) = 30 N

A.) The Torque on the pulley : circular moment ;

Force * Radius

= 30kg * 0.0160 m

= 0.48 Nm

B.) Calculate the moment of inertia of the pulley.

= 0.5mr²

= 0.5 * 2.75 * 0.0160^2m

= 0.5 * 2.75kg * 0.000256

= 0.000352kgm^-2

C.)angular acceleration :

Torque / moment of inertia

0.48 / 0.000352

= 1363.6363 rad/sec

i would say the answer is food.

hope this !