A horizontal pipe contains water at a pressure of 110 kPa flowing with a speed of 1.4 m/s. When the pipe narrows to one half its original diameter, what is (a) the speed and (b) the pressure of the water?

a

b

Explanation:

From the question we are told that  

     The pressure of the water in the pipe is  

      The speed of the water  is

       The original area of the pipe is  

       The  new area of the pipe is  

Generally the continuity equation is mathematically represented as

Here is the new velocity  

So

=>    

=>    

=>    

=>    

Generally given that the height of the original pipe and the narrower pipe are the same , then we will b making use of the  Bernoulli's equation for constant height to calculate the pressure

This is mathematically represented as

Here is the density of water with value  

=>          

=>          

he kicked it 10 feet straight up into the air? i think this works.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6