Ithrow a ball upward at 40 m/s what is the acceleration

You'll need to use the formula v2f=v2o+2aΔsvf2=vo2+2aΔs, where v2fvf2 is final velocity squared, v2ovo2 is initial velocity squared, a is acceleration (equal to g), and ΔsΔs is displacement. 

Hope this helps. 

Distance^2= yellow line ^2 (see picture) = 30^2 + 49^2so distance = squareroot of (300^2 +49^2)i dont know if this is how to solve it, but i cnt think of another way