A man goes 150 m due east and then 200 m due north how far is he from starting point

250 m

Explanation:

Since North and East are 90 degrees from each other, we can treat this as a right-angled triangle, with the distance in each direction being the sides and the distance from the starting point being the hypotenuse.

Hence, sqrt(150^2+200^2) = 250 m.

Hope this helped!

i believe the answer is a

double the distance = divide strength by 4