A 0.17 kg ball of dough is thrown straight up into the air with an initial speed of 12 m/s. The acceleration of gravity is 9.81 m/s 2 . a) What is its momentum at its maximum height? Answer in units of kg · m/s

The momentum of the ball at the maximum height is zero (0 kg.m/s).

Explanation:

Given;

mass of the ball, m = 0.17 kg

initial velocity of the ball, u = 12 m/s

acceleration due to gravity, g = 9.81 m/s²

At maximum height the final velocity of the ball, v = 0

Momentum of the ball at the maximum height is given as;

P = mv

P = (0.17)(0)

P = 0 kg.m/s

Therefore, the momentum of the ball at the maximum height is zero (0).

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get