A particle executes simple harmonic motion with an amplitude of 2.00 cm. At what positions does its speed equal one fourth of its maximum speed?

The positions are  0.0194 m  and - 0.0194 m.

Explanation:

Given;

amplitude of the simple harmonic motion, A = 2.0 cm = 0.02 m

speed of simple harmonic motion is given as;

the maximum speed of the simple harmonic motion is given as;

when the speed equal one fourth of its maximum speed

Thus, the positions are  0.0194 m and - 0.0194 m.

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