A 1400 kg car is moving at 33.8 m/s when a force is applied the opposite direction of the car's motion. The car slows down to 21.4 m/s . the force is applied for what is the magnitude of the force?

Solve for acceleration:

a = (21.4 m/s - 33.8 m/s) / (4.7 s)

a ≈ -2.6 m/s²

Solve for force:

F = (1400 kg) a ≈ -3700 N

The minus sign tells you the force points in the opposite direction of the car's motion. Its magnitude is always positive, so F = 3700 N.

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation:

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.