A 50.3-kg person, running horizontally with a velocity of 2.44 m/s, jumps onto a 13.4-kg sled that is initially at rest. (a) Ignoring the effects of friction during the collision, find the velocity of the sled and person as they move away. (b) The sled and person coast 30.0 m on level snow before coming to rest. What is the coefficient of kinetic friction between the sled and the snow

a

b

The value is            

Explanation:

From the question we are told that

      The  mass of the person is  

       The  horizontal velocity is  

       The mass of the shed is  

        The distance covered is  

Generally from the law of momentum conservation we have that

Here   is the initial velocity of the shed which is  0 m/s  

=>    

Generally the workdone by friction is mathematically represented as  

Here is the final velocity of the person and the shed when they come to rest and the value is  

 Generally this workdone  by friction is also mathematically represented as

=>        

=>      

=>        

=>                

fghbdt gjdtyg thd tghbtrg htd

step-by-step explanation:

y htf dfh drthf hdt hdthyty hty

unbalanced force

explanation: