Find the total resistance and the potential difference for the resistors connected in parallel where the amounts of the resistors are : R1=10 Ohm R2=5 Ohm R3=2 1.25 Ohm and 12V
1.25 Ohm and 15V
17 Ohm and 15V
17Ohm and 12V

Ithink the answer is a

The speed was not exceeded so it was slow

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward