Question is attached!

For Bill to dump the water on Tim, Tim should be 7.232 meters from the tree when Bill dumps the water

Explanation:

The given height above the ground at which Bill sits on the tree branch with a bucket of water, h = 4.0 meters

The speed with which Tim is approaching the tree = 8.0 meters per second

The time , t, it will take for the bucket of water to reach the ground is given by the equation of free fall as follows;

h = 1/2·g·t²

Where;

h = Height = 4.0 m

g = The acceleration due to gravity ≈ 9.8 m/s²

t = The time

Making t the subject of the above equation gives;

t = √(h/(1/2·g))

Substituting the known values gives;

t = √(4.0 m/(1/2 × 9.8 m/s²)) ≈ 0.904 s

t ≈ 0.904 seconds

Therefore, for Bill to dump the water on Tim, it should take Tim approximately 0.904 seconds to get to the tree

The distance, d, Tim will be when it will take him 0.904 seconds to get to the tree is given from the kinematic equation of speed, s, as follows;

Distance, d = Time, t × Speed, s

Where;

d = The distance

t = The time = 0.904 s

s = The speed with which Tim is approaching the tree = 8.0 m/s

Substituting the values gives;

d = 0.904 s × 8.0 m/s = 7.232 m

Therefore, the distance Tim should be when Bill throws the water = 7.232 meters

hey , the answer is c