derive formula of kinetic energy of particular having mass volume and velocity of dimensional analysis

E=1/2kmv^2

Explanation:

To get the formula...

The dimension of energy is [ M^1 L^2 T^-2]

The dimension of mass [M]=[M^1 L ^0T ^0]

Dimension of velocity[V]=[M ^0 L ^1 T ^−1]

Let [E]=k[M] ^x[V] ^y

K is constant and it remain a dimensionless quantity.

Therefore, M ^1L ^2T ^−2]=k[M ^1L ^0T ^0] x[M ^0L ^1 T ^−1] y

So, x=1,y=2

E= Kmv^2

K=1/2

Therefore E is 1/2kmv^2.

its c i just checked it

the components of a vector are the parts of the vectors that are to each other.

b perpendicular