A pool ball moving 1.33 m/s strikes an identical ball at rest. Afterward, the first ball moves 0.814 m/s at a 33.3° angle. What is the x-component and y-component of the velocity of the second ball? pls help quick

X - component = v2 = 0.650 m/s

Y - component = v2 = 0.447 m/s

Explanation:

Given that :

Conservation of momentum

m1u1 + m2u2 = m1v1 + m2v2

m = mass of pool ball ; u = initial velocity ; v = final velocity

Since the masses are identical

x - component

u1 + u2 = v1 + v2

u1 = 1.33 m/s

u2 = 0

Final speed of first ball = 0.814 m/s at an angle of 33.3° ;

v1 = 0.814*cos33.3 = 0.814 * 0.8358073 = 0.6803471 m/s

v2x = u1x + u2x - v1

v2x = 1.33 + 0 - 0.6803471

v2x = 0.6496529 m/s

v2x = 0.650 m/s

Y - component :

v1sinθ= 0.814*sin33.3 ; 0.814 * 0.5490228 = 0.4469045 m/s

v2y = 0.447 m/s

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.