In Space, an astronaut releases a wrench from his hand. The wrench has a mass of 4 grams and is traveling with a velocity of -15m/s. The Astronaut’s mass is 70kg. What is his Velocity?

The velocity of the astronaut after throwing the wrench is 8.571 × 10⁻⁴ m/s

Explanation:

The given parameters are;

The mass of the wrench the astronaut releases, m₁ = 4 grams = 0.004 kg

The speed with which the wrench is travelling, v₁ = -15 m/s

The mass of the astronaut, m₂ = 70 kg

The velocity of the astronaut after throwing the wrench = v₂

Whereby the astronaut and the wrench were initially at rest, we have the total initial momentum = 0 kg·m/s

The total final momentum = m₁×v₁ + m₂×v₂ = 0.004 × (-15) + 70 × v₂

By the conservation of momentum principle, we have;

The total initial momentum = The total final momentum

Which gives;

0 = 0.004 × (-15) + 70 × v₂

0.004 × (-15) = -70 × v₂

∴ v₂ = 0.004 × (-15)/-70 = 0.0008571

The velocity of the astronaut after throwing the wrench = v₂ = 0.0008571 m/s = 8.571 × 10⁻⁴ m/s

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

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