At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball's acceleration is 890 m/s2 and the vertical or y component of its acceleration is 1100 m/s2. The ball's mass is 0.41 kg. What is the magnitude of the net force acting on the soccer ball at this instant

580.13N

Explanation:

The magnitude of the net force is expressed using the expression

F = ma

m is the mass

a is the net acceleration

Given

Mass = 0.41kg

Get the net acceleration

a = √(ax)²+(ay)²

a = √890²+1100²

a = √792100+1210000

a = √2002100

a = 1414.96m/s²

Get the required net force acting on the ball

F = ma

F = 0.41×1414.96

F = 580.13N

Hence the net force acting on the soccer ball at this instant is 580.13N

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//